Question : The mean of the following distribution is 18. Find the frequency of the class 19-21.
Class Intervals | Frequency |
11-13 | 3 |
13-15 | 6 |
15-17 | 9 |
17-19 | 13 |
19-21 | f |
21-23 | 5 |
23-25 | 8 |
Total | Σfi=40+f |
Doubt by Gauri
Solution :
Solution :
Class Intervals (CI) | Frequency (Fi) | Class Marks (xi) | di=xi-a | fidi |
11-13 | 3 | 12 | -6 | -18 |
13-15 | 6 | 14 | -4 | -24 |
15-17 | 9 | 16 | -2 | -18 |
17-19 | 13 | 18 = a | 0 | 0 |
19-21 | f | 20 | 2 | 2f |
21-23 | 5 | 22 | 4 | 20 |
23-25 | 4 | 24 | 6 | 24 |
Total | Σfi=40+f | Σfidi=-16+2f |
Mean (x̄) = 18
By Assumed Mean Method
a = 18
Σfidi=-16+2f
Σfi=40+f
x̄ = a + Σfidi/Σfi
18 = 18 + (-16+2f)/(40+f)
18 = 18 + (-16+2f)/(40+f)
18-18 = (-16+2f)/(40+f)
0 = (-16+2f)/(40+f)
0×(40+f) = -16+2f
0 = -16+2f
16=2f
16/2 = f
0 = (-16+2f)/(40+f)
0×(40+f) = -16+2f
0 = -16+2f
16=2f
16/2 = f
f = 8