Doubt by Parth
Solution :
The tent has two parts cylinder at the bottom and cone at the top.
Total Height of the tent = 8 m
Dimensions of the cylinder
H= 5 m
H= 5 m
Radius of the cylinder
r=d/2
r=7/2 m
r=7/2 m
Dimensions of the conical part
Radius (r) = 7/2 m = 3.5 m
Height the cylinder (h)
= 8-5
= 3 m
= 3 m
Slant height of the cone (l)
l=√[r²+h²]
l=√[(3.5)²+(3)²]
l=√[12.25+9]
l=√[21.25]
l= 4.609
l=√[(3.5)²+(3)²]
l=√[12.25+9]
l=√[21.25]
l= 4.609
l=4.61 m
Now
Area of canvas
= CAS of Cone + CSA of Cylinder
= πrl+2πrH
= πr(l+2H)
= (22/7)(7/2)×[4.61+2(5)]
= 11×[4.61+10]
= 11×[14.61]
= 11×[4.61+10]
= 11×[14.61]
= 160.71 m²
Cost of 1m² canvas = ₹ 5
Cost of 160.71 m² = ₹ (5×160.71)
= ₹ 803.55
A tent of height 8 m is in the form of a right circular cylinder of radius 3m and height 4m surrounded by a right circular cone of the same radius. Find the cost of cloth required to prepare the tent at the rate of ₹ 210 per square meter.
Ans : ₹25740