Question : Case Study Based Question (CSBQ)
Due to on going Corona Virus outbreak Raj Medical store has started selling masks of descent quality. The store is selling two types of Masks Currently Type 'A' & Type 'B'. The Cost of one Type 'A' Mask is Rs. 15 and of One Type 'B' Mask is Rs. 20. In the Month of April, 2020 the store sold 100 Masks for Total Sales of Rs. 1650. Due to great demand and short supply , the store has increased the price of each type by Rs 5 from May 1,2020. In the Month of May, 2020 the store Sold 310 Masks for Total Sales of Rs 6875. On the basis of the above information, Answer any four of the following questions:-
i.) How many masks of each type were sold in the month of April?
(a) 40 Masks of type 'A' & 80 Masks of type 'B'.
(b) 60 Masks of type 'A' & 40 Masks of type 'B'.(c) 70 Masks of type 'A' & 30 Masks of type 'B'.(d) 30 Marks of type 'A' & 70 marks of type 'B'
ii.) If the store had sold 50 Masks of each type. What would be its sale in the Month of April?
(a) Rs 550
(b) Rs 560
(c) Rs 1050
(d) Rs 1750
iii.) How many masks of each type were sold in the Month of May?
(a) 175 Masks of type 'A' & 135 Masks of type 'B'.
(b) 200 Masks of type 'A' & 110 Masks of type 'B'.
(c) 110 Masks of type 'A' & 200 Masks of type 'B'.
(d) 135 Masks of type 'A' & 175 Masks of type 'B'.
iv) What percent of Masks of each type sale was increased in the Month of May, compared with the sale of with the sale of Month April?
(a) 110% in type 'A' & 180% in type 'B'.
(b) 180% in type 'A' & 110% in type 'B'.
(c) 350% in type 'A' & 150% in type 'B'.
(d) 150% in type 'A' & 350% in type 'B'.
v) What extra profit did he earned by increasing Price in May Month?
(a) Rs 1550
(b) Rs 3100
(c) Rs 1650
(d) Rs 1825
Doubt by Gurjot.
Solution :
i) In April 2020
Let the number of Type A mask sold = x
and the number of Type B mask sold = y
ATQ
x+y=100 — (1)
15x+20y=1650
5(3x+4y)=1650
3x+4y=1650/5
3x+4y=330 — (2)
Solving equation (1) and (2) by Elimination Method
(x+y=100)×3
3x+4y=330
3x+3y=300
3x+4y=330
- - -
----------
0 - y = -30
----------
-y=-30
y=30
putting in equation (1)
x+y=100
x+30=100
x=100-30
x=70
Hence,
No. of Type A Mask sold = x = 70
No. of Type B Mask sold = y = 30
So, the correct option is (c) 70 Masks of type 'A' & 30 Masks of type 'B'.
ii) Cost of 1 Mask of Type A = Rs 15
Cost of 50 Mask of Type A
= Rs (15×50)
= Rs 750
Cost of 1 Mask of Type B = Rs 20
Cost of 50 Mask of Type B
= Rs (20×50)
= Rs 1000
Total Sale in the month of April 2020
= Rs (750+1000)
= Rs 1750
Hence, the correct option would be d) Rs 1750
iii) In May 2020
Let the number of Type A mask sold = x
and the number of Type B mask sold = y
ATQ
x+y=310 — (1)
20x+25y=6875
5(4x+5y)=6875
4x+5y=6875/5
4x+5y=1372 — (2)
Solving equation (1) and (2) by Elimination Method
(x+y=310)×4
4x+5y=1375
4x+4y=1240
4x+5y=1375
- - -
----------
0 - y = -135
----------
-y=-135
y=135
putting in equation (1)
x+y=310
x+135=310
x= 310-135
x= 175
Hence,
No. of Type A Mask sold = x = 175
No. of Type B Mask sold = y = 135
So, the correct option is (a) 175 Masks of type 'A' & 135 Masks of type 'B'
iv) Percentage increase of Type A Mask
= (Final - Initial)/ Initial
= [(175-70)/70]×100
=[105/70]×100
= 10500/70
= 1050/7
= 150 %
Percentage increase of Type B Mask
= (Final - Initial)/ Initial
= [(135-30)/30]×100
=[105/30]×100
= 10500/30
= 1050/3
= 350 %
So, the correct option is d) 150% in type 'A' & 350% in type 'B'.
v) Extra Profit Earned in May by Increasing the Price
In May
No. of Type A Mask sold = 175
No. of Type B Mask sold = 135
Total Sales in May at old Price
= (175×15)+(135×20)
= 2625 + 2700
= Rs 5325
Total Sales in May at New Price
= (175×20)+(135×25)
= 3500 + 3375
= Rs 6875
Total Profit Earned = 6875-5325
= Rs 1550
So, the correct option is a) Rs 1550