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Questions based on Perimeter of Similar Triangles Theorem

Question : If the ratio of the perimeter of two similar triangles is 4:25, then the ratio of the areas is 

a) 4:25
b) 25:4
c) 625:16
d) 16:625

Doubt by Zoha

Solution :

Let two two triangles by ΔABC and ΔPQR
ΔABC~ΔPQR (Given)
Perimeter (ΔABC) / Perimeter (ΔPQR) = 4:25

We know, the ratio of the perimeter of the similar triangles is the same as the ratio of their corresponding sides

Perimeter (ΔABC) / Perimeter (ΔPQR) = AB/PQ
4:25 = AB/PQ
AB/PQ = 4:25

We also know that, the ratio of the area of two similar triangle is equal to the square of the ratio their corresponding sides.

ar(ΔABC) / ar(ΔPQR) = (AB/PQ)2
ar(ΔABC) / ar(ΔPQR) = (4/25)2
ar(ΔABC) / ar(ΔPQR) = 16:625

Hence, d) would be the correct option.

Similar Question :

The perimeters of two similar triangles ΔABC and ΔPQR are 35 cm and 45 cm respectively, then the ratio of the area of the two triangles is _____________. [CBSE SQP 2019-2020]

Solution : 

Perimeter (ΔABC) = 35 cm
Perimeter (ΔPQR) = 45 cm

Perimeter (ΔABC) / Perimeter (ΔPQR) = 35/45
Perimeter (ΔABC) / Perimeter (ΔPQR) = 7/9

Perimeter (ΔABC) / Perimeter (ΔPQR) = AB/PQ
7/9 = AB/PQ
AB/PQ = 7/9

ar(ΔABC) / ar(ΔPQR) = (AB/PQ)2
ar(ΔABC) / ar(ΔPQR) = (7/9)2
ar(ΔABC) / ar(ΔPQR) = 49:81

Practice Question :

The perimeter of two similar triangles ABC and XYZ are 60 cm and 48 cm respectively. If XY=8 cm the the length of AB would be 
a) 4 cm
b) 6 cm
c) 8 cm
d) 10 cm

Click Here for the Answer

d) is the correct option