a) 30°
b) 40°
c) 45°
d) 50°
Doubt by Saumya
Solution :
∠B=70° (Given)
∠C=50° (Given)
∠C=50° (Given)
AB/AC = BD/DC (Given)
∠BAD = ∠CAD
(Converse of Internal Angle Bisector Theorem)
(Converse of Internal Angle Bisector Theorem)
Let
∠BAD = ∠CAD = x
∠BAD = ∠CAD = x
Now, In ΔBAC
∠ABC + ∠BCA + ∠BAC = 180°
(Angle Sum Property)
(Angle Sum Property)
∠ABC + ∠BCA + ∠BAC = 180°
70°+50°+x+x = 180°
120°+2x = 180°
2x = 180°-120°
2x = 60°
x = 60°/2
x = 30°
120°+2x = 180°
2x = 180°-120°
2x = 60°
x = 60°/2
x = 30°
∠BAD = 30°
Hence, a) would be the correct option.