a) 10
b) 11
c) 12
d) 13
Doubt by Pushkar
Solution :
Let us assume that the digit at the unit place is x and the digit at the ten's place be y.
So
Original number = 10y+x
Reverse number = 10x+y
ATQ
ATQ
Perfect Square =
Original number + Reverse number
Original number + Reverse number
Perfect Square =10y+x + 10x+y
Perfect Square = 11x+11y
Perfect Square = 11(x+y)
Perfect Square = 11x+11y
Perfect Square = 11(x+y)
Clearly Least value of x+y to be a perfect square is 11.
Hence, b) would be the correct option.
Hence, b) would be the correct option.