Based on the above, answer the following questions :
(i) Find the area of the square shaped grass field. [1 Mark]
(ii)
(a) Find the area of the total field in which these horses can graze. [2 Marks]
OR
(b) If the length of the rope of each horse is increased from 7 m to 10 m, find the area grazed by one horse. [Use π=3.14] [2 Marks]
(a) Find the area of the total field in which these horses can graze. [2 Marks]
OR
(b) If the length of the rope of each horse is increased from 7 m to 10 m, find the area grazed by one horse. [Use π=3.14] [2 Marks]
(iii) What is the area of the field that is left ungrazed, if the length of the rope of each horse is 7 cm. [1 Marks]
CBSE Outside Delhi [2024] (30/3/1)
Solution :
This is a case study based question from Area Related to circles (Mensuration).
Here side of the square (a) = 20 m
Length of the rope (r) = 7 m
(i) Find the area of the square shaped grass field.
Ans :
Area of square shaped grass field
= (side)²
= a²
= (20)²
= 400 m²
= (side)²
= a²
= (20)²
= 400 m²
(ii)
(a) Find the area of the total field in which these horses can graze.Ans :
Required Area
=4×Area of sector
=4×[θ/360]×[π](r)²
=4×[90/360]×[22/7](7)²
=4×[1/4]×22×7
=22×7
=154 m²
=4×Area of sector
=4×[θ/360]×[π](r)²
=4×[90/360]×[22/7](7)²
=4×[1/4]×22×7
=22×7
=154 m²
OR
(b) If the length of the rope of each horse is increased from 7 m to 10 m, find the area grazed by one horse. [Use π=3.14]
Ans :
Here,
New Radius (r') =10 m
New Radius (r') =10 m
Area grazed by one horse when the rope is increased from 7 m to 10 m
= [θ/360]×[π](r)²
= [90/360]×[3.14](10)²
= [1/4]×314
= 78.5 m²
= [1/4]×314
= 78.5 m²
(iii) What is the area of the field that is left ungrazed, if the length of the rope of each horse is 7 cm.
Ans :
Ans :
Area of the field left ungrazed
= Area of field - area of field grazed by 4 horses
= 400 m² - 154 m²
= 246 m²
= Area of field - area of field grazed by 4 horses
= 400 m² - 154 m²
= 246 m²