Question : If secθ+tanθ=x, then secθ-tanθ will be
(A) x
(B) x²
(C) 2/x
(D) 1/x
CBSE Sample Question Paper 2026
Solution :
secθ+tanθ=x
Reciprocating both side
1/(secθ+tanθ) = 1/x
sec²θ-tan²θ/(secθ+tanθ)=1/x [∵1+tan²θ=sec²θ]
[(secθ+tanθ)(secθ-tanθ)]/(secθ+tanθ)=1/x
[∵a²-b²=(a+b)(a-b)]
secθ-tanθ=1/x
Hence, (D) 1/x, would be the correct option.