Class 10 | Chapter - 5 | Arithmetic Progression (AP)
Date of Exam - March 12, 2020
CBSE (Delhi) 2020 [Standard Paper]
[1 Mark Questions]
1.) [SET-1][SET-2][SET-3] The value of x for which 2x, (x+10) and (3x+2) are the three consecutive terms of the an AP, is
a) 6
b) -6
c) 18
d) -18
2.) [SET-1][SET-2][SET-3] The first term of the AP is p and the common difference is q, then its 10th term is
a) q+9p
b) p-9q
c) p+9q
d) 2p+9q
[ 2 Mark Questions]
3.) [SET -1] Show that (a-b)2, (a2+b2) and (a+b)2 are in AP.
[SET -2] Find the sum of the first 20 terms of the AP :
1, 4, 7, 10 . . .
[SET-3] The sum of first 7 terms of an AP is 63 and that of its next 7 terms is 161. Find the AP.
[ 4 Mark Questions]
4.) [SET-2][SET-3] The sum of four consecutive numbers in a AP is 32 and the ratio of the product of the first and last terms to the product of two middle terms is 7:15. Find the numbers. [4 Marks]
OR
Solve : 1 + 4 + 7 + 10 + . . . + x = 287 [4 Marks]
CBSE (Delhi) 2020 [Basic Paper]
[1 Mark Questions]
1.) [SET-1] The nth term of an AP is (7-4n), then what is its common difference?
[4 Mark Questions]
2) If 4 times the 4th term of an AP is equal to 18 times the 18th term of the AP, then find the 22nd term.
OR
How many terms of the AP : 24, 21, 18, . . . must be taken so that their sum is 78?
Answers / Hints
1. a)
2. c)
3. d = 2ab, 590,
4. 2,6,10,14 / 14,10,6,2 OR 40
1. - 4
2. 0 OR 4
[1 Mark Questions]
1.) [SET-1][SET-2][SET-3] The value of x for which 2x, (x+10) and (3x+2) are the three consecutive terms of the an AP, is
a) 6
b) -6
c) 18
d) -18
2.) [SET-1][SET-2][SET-3] The first term of the AP is p and the common difference is q, then its 10th term is
a) q+9p
b) p-9q
c) p+9q
d) 2p+9q
[ 2 Mark Questions]
3.) [SET -1] Show that (a-b)2, (a2+b2) and (a+b)2 are in AP.
[SET -2] Find the sum of the first 20 terms of the AP :
1, 4, 7, 10 . . .
[SET-3] The sum of first 7 terms of an AP is 63 and that of its next 7 terms is 161. Find the AP.
[ 4 Mark Questions]
4.) [SET-2][SET-3] The sum of four consecutive numbers in a AP is 32 and the ratio of the product of the first and last terms to the product of two middle terms is 7:15. Find the numbers. [4 Marks]
OR
Solve : 1 + 4 + 7 + 10 + . . . + x = 287 [4 Marks]
CBSE (Delhi) 2020 [Basic Paper]
[1 Mark Questions]
1.) [SET-1] The nth term of an AP is (7-4n), then what is its common difference?
[4 Mark Questions]
2) If 4 times the 4th term of an AP is equal to 18 times the 18th term of the AP, then find the 22nd term.
OR
How many terms of the AP : 24, 21, 18, . . . must be taken so that their sum is 78?
Answers / Hints
1. a)
2. c)
3. d = 2ab, 590,
4. 2,6,10,14 / 14,10,6,2 OR 40
1. - 4
2. 0 OR 4
Special Thanks to Sneha for SET - 1, Himansh for SET - 2 and Gurvinder for SET - 3 of Standard Maths QP
Special Thanks to Harsh for SET - 1 of Basic Maths QP
Special Thanks to Harsh for SET - 1 of Basic Maths QP
CBSE (Delhi) 2019
[2 Mark Questions]
1. Which term of the AP 3,15, 27, 39, . . . will be 120 more than its 21st term?
OR
If Sn, the sum of first n terms of the AP is given by Sn = 3n2-4n, find the nth term.