Doubt by Yathartha, Saumya
Solution :
Dimensions of Cuboidal Cistern
L = 150 cm
Dimensions of Cuboidal Cistern
L = 150 cm
B = 120 cm
H = 110 cm
Total volume of the cistern = LBH
= 150×120×110
= 1980000 cm³
= 150×120×110
= 1980000 cm³
Volume of water present in the cistern = 129600 cm³
Volume of water required to fill the cistern
= 1980000 - 129600
= 1850400 cm³
= 1980000 - 129600
= 1850400 cm³
Dimensions of each brick
l = 22.5 cm
l = 22.5 cm
b = 7.5 cm
h = 6.5 cm
Volume of each brick
= 22.5×7.5×6.5
= 1096.875 cm³
= 22.5×7.5×6.5
= 1096.875 cm³
Let the number of bricks required to fill the cistern up to the brim = n
Volume of water increased by 1 bricks
= Volume of 1 brick - 1/17(Volume of 1 brick)
= Volume of 1 brick (1-1/17)
= Volume of 1 brick (16/17)
= Volume of 1 brick - 1/17(Volume of 1 brick)
= Volume of 1 brick (1-1/17)
= Volume of 1 brick (16/17)
= 1096.875×(16/17)
Volume of water increased by n bricks
= 1096.875×(16/17)×n — (1)
Volume of water required to fill the cistern
Volume of water increased by n bricks
= 1096.875×(16/17)×n — (1)
Volume of water required to fill the cistern
= 1850400 cm³ — (2)
Equating eq (1) and (2)
1096.875×(16/17)×n = 1850400
n = (1850400 × 17) / (16×1096.875)
n = 31456800/17550
n = 1792.41
n = 1792 (approx)
Equating eq (1) and (2)
1096.875×(16/17)×n = 1850400
n = (1850400 × 17) / (16×1096.875)
n = 31456800/17550
n = 1792.41
n = 1792 (approx)
Hence, 1792 bricks can be put in to the cistern without overflowing the water.