Doubt by Vikrant
Solution :
Total number of flags = 27
Distance between the any two consecutive spots where the flags will be placed = 2 m
All the flags are placed at the middle flag i.e. (27+1)/2 = 14th flag.
All the flags are placed at the middle flag i.e. (27+1)/2 = 14th flag.
Ruchi will start from the central (14th flag) flag
First she will place 13 flags on left side and she will place the remaining 13 flags on the right side one by one.
First she will place 13 flags on left side and she will place the remaining 13 flags on the right side one by one.
Distance covered by her in placing first flag on left = 2(2) = 4m
Distance covered by her in placing first flag on left = 2(2+2) = 8m
Distance covered by her in placing first flag on left = 2(2+2+2) = 12m
and so on
and so on
4, 8, 12. . .
This is an AP with First Term (a) = 4 and and common difference (d) = 8-4 = 4
Now, total distance covered by here in placing 13 flags on the left
S1=n/2[2a+(n-1)d]
S1=13/2[2(4)+(13-1)(4)]
S1=13/2[8+12(4)]
S1=13/2[8+48]
S1=13/2[56]
S1=13×28
S1=364
S1=n/2[2a+(n-1)d]
S1=13/2[2(4)+(13-1)(4)]
S1=13/2[8+12(4)]
S1=13/2[8+48]
S1=13/2[56]
S1=13×28
S1=364
Similarly total distance covered by her in placing 13 flags on the right will be
S2=364
S2=364
Total distance covered by her in placing all the flags
=S1+S2
=364+364
=728
=S1+S2
=364+364
=728
The maximum distance she travelled carrying a flag will be the distance between the middle flag and the extreme 13th flag
= 2×13
= 26 m
= 2×13
= 26 m