Doubt by Divya
Solution :
In a non leap year, there are 365 days which can be divided as 52 Full Weeks + 1 Additional day.
This one extra days could be
1.) (Mondyay)
2.) (Tuesday)
3.) (Wednesday)
4.) (Thursday)
5.) (Friday)
6.) (Saturday)
7.) (Sunday)
Total Possible outcomes = 7
In order to have 52 sundays, this extra day should not be (Sunday)
So, favourable outcomes = {(Mondyay), (Tuesday), (Wednesday), (Thursday), (Friday), (Saturday)}= 6
P(52 sundays in a non-leap year) = 6/7