Question: If sin(α+β)=1, α=60°, then the value of [cos(α-β)/cosβ]2 = ________
a) 0
b) 1/2
c) (√3)/2
d) 1
Doubt by Muskan
Solution:
sin(α+β)=1
sin(α+β)=sin90°
α+β=90°
60°+β=90° [∵ α=60°]
β=90°-60°
β=30°
Now,
=[cos(60°-30°)/cos30°]2
=[cos(30°)/cos30°]2
=[1]2
=1
∴ d) is the correct option.