Doubt by Yathartha
Solution :
p(x)=x2-2x+3
a=1
a=1
b=-2
c=3
Sum of Zeroes
α+β = -b/a
α+β = -(-2)/1
α+β = 2
Product of Zeroes
αβ = c/a
αβ = 3/1
αβ = 3
For New Polynomial
Sum of Zeroes (S)
S= (α+2)+(β+2)
S= α+β+4
S= 2+4
S= 6
Sum of Zeroes (S)
S= (α+2)+(β+2)
S= α+β+4
S= 2+4
S= 6
Product of Zeroes (P)
P= (α+2)(β+2)
P= αβ+2α+2β+4
P= αβ+2(α+β)+4
P= 3+2(2)+4
P= 3+4+4
P=11
New Polynomial will be given by
p'(x)=x²-Sx+P
p'(x)=x²-(6)x+11
P= (α+2)(β+2)
P= αβ+2α+2β+4
P= αβ+2(α+β)+4
P= 3+2(2)+4
P= 3+4+4
P=11
New Polynomial will be given by
p'(x)=x²-Sx+P
p'(x)=x²-(6)x+11
p'(x)=x²-6x+11
which is the required polynomial.