Question : If the 17th term of an AP exceeds the 10th term by 7. Find the common difference.
Doubt by Gauri
Solution :
ATQ
Solution :
ATQ
a17-a10 = 7 — (1)
We know,
an=a+(n-1)d
a17=a+(17-1)d
a17=a+16d
We know,
an=a+(n-1)d
a17=a+(17-1)d
a17=a+16d
similarly
a10=a+9d
Putting the value of a17 and a10 in equation (1)
a+16d-(a+9d) = 7
a+16d-a-9d=7
16d-9d=7
7d=7
d=7/7
d=1
Hence, the required common difference is 1.
7d=7
d=7/7
d=1
Hence, the required common difference is 1.