If figure, AB||ED. If AD=3x+19, EB=3x+4, DC=x+3 . . .

Question : If figure, AB||ED. If AD=3x+19, EB=3x+4, DC=x+3 and CE=x then find the value of x.

Doubt by Riddhi

Solution : 

AB||ED (Given)

AD/DC=BE/EC (By BPT)

(3x+19)/(x+3) = (3x+4)/(x)
(3x+19)(x)= (3x+4)(x+3)
3x²+19x=3x²+9x+4x+12

19x=13x+12

19x-13x=12

6x=12

x=12/6
x=2