[CBSE 2025] 30x+44y=10, 40x+55y=13 Solve the following system of equations algebraically . . .

Question : Solve the following system of equations algebraically : 

30x+44y=10 

40x+55y=13

CBSE 2025

Solution : 

30x+44y=10 — (1)

40x+55y=13 — (2) 

[30x+44y=10]×4

[40x+55y=13]×3

120x+176y=40
120x+165y=39

-       -          - 
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0x   +  11y = 1
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11y=1
y=1/11

Putting in equation (1) 
30x+44y=10
30x+44(1/11)=10

30x+4=10
30x=10-4
30x=6
x=6/30

x=1/5
Hence, x=1/5 and y=1/11.