(A) 142296
(B) 142396
(C) 142496
(D) 142596
Doubt by Veer
Solution :
Side of cube (a) = 22 cm
Diameter of spherical marble (d) = 0.5 cm
Radius of spherical marble (r)
= 0.5/2
= 5/20
=1/4 cm
Radius of spherical marble (r)
= 0.5/2
= 5/20
=1/4 cm
Let number of marbles cube can accomodate be x
ATQ =
Volume of Cube - Volume of empty space = x × Volume of each marble
Volume of cube - ⅛ (Volume of cube) = x × Volume of each marble
Volume of cube (1-⅛) = x × Volume of each marble
⅞ Volume of cube = x × Volume of each marble
