i) 3+√7, 3-√7
ii) √3, -2√3
Doubt by Aditi
Solution :
i) Here
α = 3+√7
β = 3-√7
We know, the quadratic equation is given by
β = 3-√7
We know, the quadratic equation is given by
p(x) = x²-(α+β)x+αβ
p(x) = x²-(3+√7+3-√7)x+(3+√7)(3-√7)
p(x) = x²-(3+3)x+[(3)²-(√7)²]
p(x) = x²-6x+[9-7]
p(x) = x²-6x+2
p(x) = x²-(3+√7+3-√7)x+(3+√7)(3-√7)
p(x) = x²-(3+3)x+[(3)²-(√7)²]
p(x) = x²-6x+[9-7]
p(x) = x²-6x+2
which is the required quadratic equation.
ii) Here
α = √3,
β = -2√3
β = -2√3
p(x) = x²-[√3+(-2√3)]x+√3(-2√3)
p(x) = x²-[√3-2√3]x-6
p(x) = x²-[-√3]x-6
p(x) = x²-[-√3]x-6
p(x) = x²+√3x-6
which is the required quadratic equation.