Doubt by Mehak
Solution :
Let the speed of car at A = x km/h
and the speed of car at B = y km/h
Case I : When both the cars move in the same direction then they meet at point C after 8 hours.
A_____B____C
We know,
We know,
Speed = Distance/Time
Distance = Speed × Time
Distance covered by car A in 8 hours
AC = x(8) = 8x km
AC = x(8) = 8x km
Distance covered by car B in 8 hours
BC = y(8) = 8y km
BC = y(8) = 8y km
AB = 80 km (Given)
ATQ
AC-BC=AB
8x-8y=80
8(x-y)=80
x-y=80/8
x-y=10 — (1)
ATQ
AC-BC=AB
8x-8y=80
8(x-y)=80
x-y=80/8
x-y=10 — (1)
Case 2 : When both the cars move towards each other then they are meet point C after 1 hour 20 minutes i.e.
1 hours + (20/60) hours
= 1 hours + 1/3 hours
= 4/3 hours
1 hours + (20/60) hours
= 1 hours + 1/3 hours
= 4/3 hours
A____C_____B
Distance covered by car A in 4/3 hours
AC = x(4/3) = 4x/3 km
AC = x(4/3) = 4x/3 km
Distance covered by car B in 4/3 hours
BC = y(4/3) = 4y/3 km
BC = y(4/3) = 4y/3 km
AB = 80 km (Given)
ATQ
AC+BC=AB
4x/3+4y/3=80
(4/3)(x+y)=80
x-y=[80×3]/4
x+y=60 — (2)
(4/3)(x+y)=80
x-y=[80×3]/4
x+y=60 — (2)
solving equation (1) and (2)
x+y=60
x- y=10
- + -
- + -
---------------
0 + 2y = 50
0 + 2y = 50
---------------
y=50/2
y=25
putting in equation (1)
y=25
putting in equation (1)
x-25=10
x=10+25
x=35
x=10+25
x=35
Hence, the speed of car at A = 35 km/h
and speed of car at B = 25 km/h
and speed of car at B = 25 km/h