Question : For what positive values of k, the quadratic equation 3x²–kx+3=0 has equal roots?
Doubts by Mehak
Solution :
3x²–kx+3=0
a = 3
b = -k
c = 3
D = b²-4ac
D = (-k)²-4(3)(3)
D = k²-36
0 = k²-36 [∵ Roots are equal]
36 = k²
k = ±√36
k=±6
But k≠-6
Hence,
k=6