Doubt by Zoha
Solution :
Let the actual marks scored by Ajita in her test be x.
ATQ
9(x+10)=x²
9x+90=x²
0=x²-9x-90
x²-9x-90=0
Factorising by Splitting the Middle Terms
x²-9x-90=0
Factorising by Splitting the Middle Terms
x²-(15-6)x-90=0
x²-15x+6x-90=0
x(x-15)+6(x-15)=0
(x+6)(x-15)=0
x+6=0
x=-6
x²-15x+6x-90=0
x(x-15)+6(x-15)=0
(x+6)(x-15)=0
x+6=0
x=-6
but marks can't be -ve.
Rejected
Rejected
OR
x-15=0
x=15
x-15=0
x=15
Hence, the actual marks scored by Ajita in the test is 15.